1. Tardigrade
  2. Question
  3. Chemistry
  4. A solution of sucrose (molar mass =342 gmol- 1 ) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be ( Kf for water =1.86 Kkgmol- 1 )

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Q. A solution of sucrose (molar mass $=342 \, gmol^{- 1}$ ) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be

( $K_{f}$ for water $=1.86 \, Kkgmol^{- 1}$ )

NTA AbhyasNTA Abhyas 2020Solutions

Solution:

$\Delta T_{f}=K_{f}.\frac{w}{m o l . w t . \times W_{s o l .}}\times 1000$

$\Delta T_{f}=\left(\frac{68.5 \times 1000}{342 \times 1000}\right)\times 1.86$

$\Delta T_{f}=0.372$

F.pt. of solution $=0^{o}C-0.372=-0.372C$