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Q. A solution of sodium sulphate in water is electrolysed using inert electrodes. The products at the cathode and anode are respectively

Electrochemistry

Solution:

At cathode : $2 H ^{+}+2 e^{-} \longrightarrow H _{2}$

At anode $: 2 OH ^{-} \longrightarrow H _{2} O +1 / 2 O _{2}+2 e^{-}$