Sodium borate in solution undergoes hydrolysis and gives a strong base (sodium hydroxide) and a weak acid $ ({{H}_{3}}B{{O}_{3}}). $ Hence, its solution will be basic and consequently the pH will be > 7. $ N{{a}_{3}}B{{O}_{3}}+3{{H}_{2}}O\xrightarrow{{}}\underset{weak}{\mathop{{{H}_{3}}B{{O}_{3}}}}\,+\underset{strong}{\mathop{3NaOH}}\, $