1. Tardigrade
  2. Question
  3. Chemistry
  4. A solution of protein (extracted from crabs) was prepared by dissolving 0.75 g in 125 cm3 of an aqueous solution. At 4°C an osmotic pressure rise of 2.6 mm of the solution was observed. Then molecular weight of protein is (Assume density of solution is 1.00 g/cm3)

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Q. A solution of protein (extracted from crabs) was prepared by dissolving $0.75 \,g$ in $125\, cm^3$ of an aqueous solution. At $4^{\circ}C$ an osmotic pressure rise of $2.6\, mm$ of the solution was observed. Then molecular weight of protein is (Assume density of solution is $1.00 \,g/cm^3$)

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Solution:

Given $h = 2.6\, mm$
$\therefore \, \pi=hd\, g =\frac{2.6}{10}\times1\times980$ dyne / $cm^{2}$
Also, $\pi=\frac{w}{Vm} RT $
$\therefore \, \frac{2.6\times1\times980}{10}=\frac{0.75\times8.314\times10^{7}\times277}{125\times m}$
$m=5.4\times10^{5}$