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  4. A solution of Ni(NO3)2 is electrolysed between platinum electrodes using 0.1 Faraday electricity. How many mole of Ni will be deposited at the cathode?

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Q. A solution of $Ni(NO_3)_2$ is electrolysed between platinum electrodes using $0.1$ Faraday electricity. How many mole of $Ni$ will be deposited at the cathode?

JEE MainJEE Main 2019Electrochemistry

Solution:

0.1 eq. of $Ni^{+2}$ will be discharged.
No. of eq = (No of moles) $\times$ (n-factor)
0.1 = (No. of moles) $\times$ 2
No. of moles of Ni = $\frac{0.1}{2} = 0.05 $