1. Tardigrade
  2. Question
  3. Chemistry
  4. A solution of Fe 2( SO 4)3 is electrolyzed for ' x ' min with a current of 1.5 A to deposit 0.3482 g of Fe. The value of x is [nearest integer] Given: 1 F =96500 C mol -1 Atomic mass of Fe =56 g mol -1

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A solution of $Fe _{2}\left( SO _{4}\right)_{3}$ is electrolyzed for ' $x$ ' min with a current of $1.5$ A to deposit $0.3482 \,g$ of $Fe$. The value of $x$ is____ [nearest integer]
Given : $1 \,F =96500 \,C\, mol ^{-1}$
Atomic mass of $Fe =56 \,g\, mol ^{-1}$

JEE MainJEE Main 2022Electrochemistry

Solution:

$Fe ^{3+}+3 e ^{-} \longrightarrow Fe$
$3 F \longrightarrow 1$ mole $Fe$ is deposited
For $56\, g \longrightarrow 3 \times 96500$ (required charge)
For $1 \,g \longrightarrow \frac{3 \times 96500}{56}$ (required charge)
For $0.3482 \,g \longrightarrow \frac{3 \times 96500}{56} \times 0.3482$
$=1800.06$
$Q=$ it
$1800.06=1.5\, t$
$t =20 \min$