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Q. A solution of $CuSO_4$ is electrolysed for $10$ minutes with a current of $1.5$ amperes. What is the mass of copper deposited at the cathode?

Electrochemistry

Solution:

$W = \frac{I\,t\,E}{96500}$
where $I = 1.5 \,A$
$t = 10 \times 60 = 600\,s$
$E = \frac{63.5}{2} = 31.75$
$\therefore W = \frac{1.5 \times 600 \times 31.75}{96500}$
$ = 0.296\,g$