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Q. A solution of $Al_{2}(SO_{4})_{3}$ {$d=1.253 gm/ml$} contain $22\%$ salt by weight. The molarity, normality and molality of the solution is

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Solution:

Molarity $= \frac{\% \times10\times d}{GMM}=\frac{22\times10\times1.253}{342}=0.805\,M$
Normality $= \frac{\% \times10\times d}{GEM}=\frac{22\times10\times1.253}{342 6}=4.83\,N $
Molality $=\frac{22\times1000}{342\left(100-22\right)}=0.825 \,m$