1. Tardigrade
  2. Question
  3. Chemistry
  4. A solution of 0.5 g of a solute (molar mass =150 g mol- 1 ) in 50 g of a solvent yields a boiling point elevation of 0.40K . Another solution of 0.60g of an unknown solute in the same mass of solvent exhibits a boiling point elevation of 0.8 K . The molar mass of unknown solute is :

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Q. A solution of $0.5\,g$ of a solute (molar mass $=150\,g\,mol^{- 1}$ ) in $50\,g$ of a solvent yields a boiling point elevation of $0.40K$ . Another solution of $0.60g$ of an unknown solute in the same mass of solvent exhibits a boiling point elevation of $0.8\,K$ . The molar mass of unknown solute is :

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