1. Tardigrade
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  3. Chemistry
  4. A solution obtained on mixing 0.1 N , 50 mL HCl and 0.1 N , 50 mL NaOH. The value of pH of the solution will be

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Q. A solution obtained on mixing $0.1\, N , 50 \,mL$ $HCl$ and $0.1 \,N , 50\, mL\, NaOH$. The value of $pH$ of the solution will be

Rajasthan PETRajasthan PET 2001

Solution:

$ HCl+NaOH\xrightarrow[{}]{{}}NaCl+{{H}_{2}}O $ Equivalent number of $ HCl=\frac{0.1\times 50}{1000}=0.005 $ Equivalent number of $ NaOH $ $ =\frac{0.1\times 50}{1000}=0.005 $ Equivalent of $ HCl= $ Equivalent of $ NaOH $ $ 0.005\equiv 0.005 $ Hence, solution is neutral ie., $ pH=7 $