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Q. A solution containing $Mn^{2+}$, $Fe^{2+}$, $Zn^{2+}$ and $Hg^{2+}$ with a molar concentration of $10^{-3}\, M$ each is treated with $10^{-16}\, M$ sulphide ion solution. Which ions will precipitate first if $K_{sp}$ of $MnS$, $FeS$, $ZnS$ and $HgS$ are $10^{-15}$, $10^{-23}$, $10^{-20}$ and $10^{-54}$ respectively?

Equilibrium

Solution:

$M^{2+}+S^{2-} \to MS$
Lower the value of $K_{sp}$, lower will be solubility. Hence, $HgS$ will precipitate first.