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Q. A solution containing 8.6 g urea in one litre was found to be isotonic with a 5% (wt./vol.) solution of an organic non-volatile solute. The molecular weight of latter is:

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Solution:

For two non-electrolytic solutions if isotonic $C_{1} = C_{2}$
$\therefore \frac{8.6}{60 \times 1}= \frac{5\times 1000}{m \times 100}$
$\therefore m= 348.9$