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Q. A solution containing $62\, g$ ethylene glycol in $250 \,g$ water is cooled to $-10^{\circ}C$. If $K_f$ for water is $1.86\, K\, kg \,mol^{-1}$, the amount of water (in g) separated as ice is :

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Solution:

$\Delta T_f = k_f. m $
$10 = 1.86 \times \frac{62 / 62}{W_{kg}}$
$W = 0.186 \; kg$
$\Delta W = (250 - 186) = 64 \; gm $