Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
A solution containing 62 g ethylene glycol in 250 g water is cooled to -10°C. If Kf for water is 1.86 K kg mol-1, the amount of water (in g) separated as ice is :
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. A solution containing $62\, g$ ethylene glycol in $250 \,g$ water is cooled to $-10^{\circ}C$. If $K_f$ for water is $1.86\, K\, kg \,mol^{-1}$, the amount of water (in g) separated as ice is :
JEE Main
JEE Main 2019
Solutions
A
32
9%
B
48
14%
C
16
13%
D
64
64%
Solution:
$\Delta T_f = k_f. m $
$10 = 1.86 \times \frac{62 / 62}{W_{kg}}$
$W = 0.186 \; kg$
$\Delta W = (250 - 186) = 64 \; gm $