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Q. A solid sphere of radius $r$ is revolving about one of its diameters with an angular velocity $\omega$. If it suddenly expands uniformly so that its radius increases to $n$ times its original value, then its angular velocity becomes

KEAMKEAM 2020

Solution:

$I_{1} \omega_{1}=I_{2} \omega_{2}$
$\frac{2}{5} m r^{2} \omega=\frac{2}{5} m\left(r'\right)^{2} \times \omega_{2}$
$r^{2} \omega=(n r)^{2} \omega_{2}$
$r^{2} \omega=n^{2} r^{2} \omega_{2}$
$\omega_{2}=\frac{\omega}{n^{2}}$