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Q.
A solid sphere is in pure rolling motion on an inclined surface having inclination $\theta$
IIT JEEIIT JEE 2006System of Particles and Rotational Motion
Solution:
In case of pure rolling,
$f=\frac{m g \sin \theta}{1+\frac{m R^{2}}{I}} \text { (upwards) }$
$\therefore f \propto \sin \theta$
Therefore, as 0 decreases force of friction will also decrease.