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Q. A solid sphere and solid cylinder of identical radii approach an incline with the same linear velocity (see figure). Both roll without slipping all throughout. The two climb maximum heights $h_{sph}$ and $h_{cyl}$ on the incline. The ratio $\frac{h_{sph}}{h_{cyl}}$ is given by :Physics Question Image

JEE MainJEE Main 2019System of Particles and Rotational Motion

Solution:

for solid sphere
$\frac{1}{2} mv^{2} + \frac{1}{2} . \frac{2}{5} mR^{2} . \frac{v^{2}}{R^{2}} =mgh_{sph} $
for solid cylinder
$ \frac{1}{2}mv^{2} + \frac{1}{2} . \frac{1}{2} mR^{2} . \frac{v^{2}}{R^{2}} = mgh_{cyl} $
$ \Rightarrow \frac{h_{sph}}{h_{cyl}} = \frac{7 /5}{3 /2} = \frac{14}{15} $