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Q. A solid cylinder of mass $20 \,kg$ and radius $10\, cm$ rotates about its axis with angular velocity $10\, rad / s$. The angular momentum of the cylinder about its axis is

Solution:

$L =I \omega=\frac{m R^{2}}{2} \omega $
$=\frac{20 \times 0.1^{2} \times 10}{2} $
$=1 \,Js $