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Tardigrade
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Physics
A solid cylinder of mass 20 kg and radius 10 cm rotates about its axis with angular velocity 10 rad / s. The angular momentum of the cylinder about its axis is
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Q. A solid cylinder of mass $20 \,kg$ and radius $10\, cm$ rotates about its axis with angular velocity $10\, rad / s$. The angular momentum of the cylinder about its axis is
A
10 Js
B
1 Js
C
0.1 Js
D
5 Js
Solution:
$L =I \omega=\frac{m R^{2}}{2} \omega $
$=\frac{20 \times 0.1^{2} \times 10}{2} $
$=1 \,Js $