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Q.
A solid $ABC$ has $A , B$ and $C$ arranged as below. The formula of solid is
The Solid State
Solution:
$A \rightarrow$ present at body centre in given figure
So, its number $=1 \times 1=1$ (contributed completely) $\rightarrow A$
$B \rightarrow$ present at corners $=\underset{(\text { Total atom })}{8} \times \underset{\text{(Contribution)}}{\frac{1}{8}} = 1 \,\,\,\,\rightarrow B$
$C \rightarrow$ Present at two opposite face $\rightarrow \underset{\text{(Total 2atomsat face)
}}{2} \times \underset{\text{(Contribution at each face)}}{\frac{1}{2}} = 1 \,\,\,\rightarrow C$
So, formula $ABC$
