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  4. A solid AB crystallises in NaCl structure. The anion B -form fcc lattice, while the cation A + occupy all the octahedral holes. If all the particles as shown in the figure are removed, then the formula of solid becomes :-

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Q. A solid AB crystallises in $NaCl$ structure. The anion $B ^{-}$form fcc lattice, while the cation $A ^{+}$ occupy all the octahedral holes. If all the particles as shown in the figure are removed, then the formula of solid becomes :-Chemistry Question Image

The Solid State

Solution:

$A^+$
$4 \times \frac{1}{8} + 4 \frac{1}{2}$
$ \frac{1}{2} + 2$
$ 2.5$
$B^-$
$10 \times \frac{1}{4}$
$ 2.5$
$AB$