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  4. A solenoid with an air core has length 48 π cm, area of cross section 12 cm 2 and 1200 turns. Self inductance of the solenoid is :-

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Q. A solenoid with an air core has length $48 \pi cm$, area of cross section $12\, cm ^{2}$ and $1200$ turns. Self inductance of the solenoid is :-

Solution:

$L =\frac{\mu_{0} N ^{2} A }{\ell}$
$=\frac{4 \pi \times 10^{-7} \times(1200)^{2} \times\left(12 \times 10^{-4}\right)}{48 \pi \times 10^{-2}}$
$=1.44\, mH$