Question

A solenoid having a length $25cm$ and total nnumber of turns equal to $500$ , carries a current of $15A$ . If we consider it to be a magnet then find its magnetization.

• A. $3\pi \, Am^{- 1}$
• B. $30000 \, Am^{- 1}$
• C. $30000\pi \, Am^{- 1}$
• D. $300 \, Am^{- 1}$

Answer 1

Answer: (B)

$Volume \, = \, Al$
$Magnetization \, \overset{ \rightarrow }{M}=\frac{m a g n e t i c \, m o n e n t \, }{V o l u m e \, }$
$=\frac{\left(N o . \, o f \, t u r n s\right) \times \left(C u r r e n t\right) \times A r e a}{V o l u m e}$
$=\frac{N \, I \, A}{A \, l}$
$=\frac{N I}{l} \, $
$=\frac{500 \times 15 \times 100}{25}$
$=60\times 500$
$=30\times 10^{3}$
$=30000 \, Am^{- 1}$