1. Tardigrade
  2. Question
  3. Physics
  4. A solenoid 30 cm long is made by winding 2000 loops of wire on an iron rod whose cross-section is 1.5 cm2 .If the relative permeability of the iron is 6000. What is the self-inductance of the solenoid?

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A solenoid $30\, cm$ long is made by winding $2000$ loops of wire on an iron rod whose cross-section is $1.5 \, cm^2$ .If the relative permeability of the iron is $6000$. What is the self-inductance of the solenoid?

VITEEEVITEEE 2014Electromagnetic Induction

Solution:

Self-inductance of the solenoid
$L =\frac{\mu_{r} \cdot \mu_{0} N^{2} A}{I}$
$=\frac{600 \times 4 \pi \times 10^{-7} \times(2000)^{2} \times(1.5) \times 10^{-4}}{0.3}$
$=1.5\, H$