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  4. A sodium hydroxide solution has pH =12 .( pH = log (1/( H +))) 100 mL of this solution has NaOH

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Q. A sodium hydroxide solution has $pH =12 .\left( pH =\log \frac{1}{\left( H ^{+}\right)}\right) 100\, mL$ of this solution has $NaOH$

Some Basic Concepts of Chemistry

Solution:

$pH =12$
$\therefore\left[ H ^{+}\right]=10^{-12} M$
${\left[ OH ^{-}\right]=10^{-2} M =10^{-2} mol L ^{-1} }$
$=10^{-3} mol$ per $100 \,mL$
$=10^{-3} \times 40\, g \,NaOH$ per $100 \,mL$
$=0.04\, g$