Q. A sodium cation has a different number of electrons from
BHUBHU 2010
Solution:
Species
Number of electrons
$Na ^{+}$
$(11-1)=10$
$O ^{2-}$
$(8+2)=10$
$F ^{-}$
$(9+1)=10$
$Li ^{+}$
$(3-1)=2$
Thus, $Na ^{+}$has different number of electrons from $Li ^{+}$.
| Species | Number of electrons |
|---|---|
| $Na ^{+}$ | $(11-1)=10$ |
| $O ^{2-}$ | $(8+2)=10$ |
| $F ^{-}$ | $(9+1)=10$ |
| $Li ^{+}$ | $(3-1)=2$ |