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  4. A small piece of metal wire is dragged across the gap between the pole pieces of a magnet in 0.5 second. The magnetic flux between the pole pieces is known to be 8 × 10-4 Wb. The emf induced in the wire is

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Q. A small piece of metal wire is dragged across the gap between the pole pieces of a magnet in 0.5 second. The magnetic flux between the pole pieces is known to be 8 × $10^{-4}$ Wb. The emf induced in the wire is

VITEEEVITEEE 2006

Solution:

Induced emf e=$\frac{-d\phi}{dt}.$Assuming, small
change in flux $d\phi=8×10^{-4}$Wb
change in time dt== 0.5s
$|e|=\frac{8×10^{-4}}{0.5}=\frac{80×10^{-4}}{5}$
=16×$10^{-4}=1.6×10^{-3}V=1.6mV$