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Q. A small coin is resting on the bottom of a beaker filled with liquid. A ray of light from the coin travels upto the surface of the liquid and moves along its surface.
How fast is the light travelling in the liquid?Physics Question Image

AIPMTAIPMT 2007

Solution:

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$ \frac{1}{\mu}=\sin \theta_{C} =\frac{3}{5}$
$ \Rightarrow \mu=\frac{5}{3} $
$\Rightarrow v =\frac{ c }{\mu} =\frac{3 \times 10^{8}}{5 / 3}=\frac{9}{5} \times 10^{8} $
$=1.8 \times 10^{8}\, ms ^{-1} $