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Q. A small coil is introduced between the poles of an electromagnet so that its axis coincides with the magnetic field direction. The number of turns is n and the cross-sectional area of the coil is $A$. When the coil turns through $180^{\circ}$ about its diameter, the charge flowing through the coil is $Q$. The total resistance of the circuit is $R$. What is the magnitude of the magnetic induction?

VITEEEVITEEE 2010

Solution:

Induced charge $Q=-\frac{n B A}{R}\left(\cos \theta_{2}-\cos \theta_{1}\right)$
$=-\frac{n B A}{R}\left(\cos 180^{\circ}-\cos 0^{\circ}\right)$
$\Rightarrow B=\frac{Q R}{2 n A}$