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  4. A slab of material of refractive index 2 shown in figure has a curved surface APB of radius of curvature 10 cm and a plane surface CD. On the left of APB is air and on the right of CD is water with refractive indices as given in the figure. An object O is placed at a distance of 15 cm from the pole P as shown. The distance of the final image of O from P, as viewed from the left is......

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Q. A slab of material of refractive index 2 shown in figure has a curved surface APB of radius of curvature 10 cm and a plane surface CD. On the left of APB is air and on the right of CD is water with refractive indices as given in the figure. An object O is placed at a distance of 15 cm from the pole P as shown. The distance of the final image of O from P, as viewed from the left is......Physics Question Image

IIT JEEIIT JEE 1991

Solution:

Rays starting from O will suffer single refraction from
spherical surface APB. Therefore, applying
$\frac{\mu_2}{v}-\frac{\mu_1}{u}=\frac{\mu_2-\mu_1}{R}$
$\frac{1.0}{v}-\frac{2.0}{-15}=\frac{1.0-2.0}{-10}$
$ \frac{1}{v}=\frac{1}{10}-\frac{1}{7.5}$
or $ $v = - 30 cm
Therefore, image of O will be formed at 30 cm to the right of
P.
Note that image will be virtual. There will be no effect of
CED.

Solution Image