Thank you for reporting, we will resolve it shortly
Q.
A single force acts on a particle situated on the negative $x$-axis. The torque about the origin is in the positive $z$-direction. The force is
Solution:
$\tau = \vec{r} \times \vec{F}$
$\Rightarrow +\hat{k} = [-\hat{i}]\times [\hat{F}]$
$\therefore \hat{F} = - \hat{j} $
So, force is in the negative $y$ direction.