Q.
A single conservative force $F(x)$ acts on a $1.0- kg$ particle that moves along the $x$-axis. The potential energy $U(x)$ is given by $U(x)=20+(x-2)^{2}$ where $x$ is in meters. At $x=5.0\, m$, the particle has a kinetic energy of $20\, J$.
The maximum kinetic energy of the particle and the value of $x$ at which maximum kinetic energy occurs are
Work, Energy and Power
Solution: