Question

A sine wave has an amplitude A and wavelength $\lambda$ . Let V be the wave velocity and maximum velocity of a particle in the medium. Then

• A. $V=\upsilon\,I\, 2\pi\lambda$
• B. $V=\upsilon\,if\, \lambda=\frac{3A}{2\pi}$
• C. V cannot be equal to $\upsilon$
• D. $V=\upsilon\,if\, A=\frac{\lambda}{2\pi}$

Answer 1

Answer: (D)

Using $\upsilon_p = \frac{2\pi A}{\lambda} \upsilon_{\omega}$ when $\upsilon_p = \upsilon_{\omega}$,
we get, A = $\frac{\lambda}{2 \pi}$.