Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A simple pendulum is suspended in a lift which is going up with an acceleration of $5 \,m / s ^{2}$. An electric field of magnitude $5 \,N / C$ and directed vertically upward is also present in the lift. The charge of the bob is $1 \, \mu C$ and mass is $1 \,mg$. Taking $g=\pi^{2}$ and length of the simple pendulum $1 \,m$, the time period of the simple pendulum (in sec) is____

Electric Charges and Fields

Solution:

$T=2 \pi \sqrt{\frac{l}{g_{ eff }}}$
image
$g_{ \text{eff} }=g-\frac{q E}{M}+5=15-\frac{1 \times 5 \times 10^{-6}}{1 \times 10^{-6}}$
$g_{ \text{eff} }=10=\pi^{2}$
$T=2 \,\sec$