Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A simple harmonic motion having an amplitude $A$ and time period $T$ is represented by the equation : $y = 5 \sin \pi (t + 4) m$
Then the values of $A$ (in m) and $T$ (in sec) are :

Oscillations

Solution:

$A =5, \omega=\pi=\frac{2 \pi}{ T }, T =2$