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Q. A shuttle cork hitted upward from badminton racket with a velocity of $50\, m / s$ and it reaches $3\, m$ from the hitting point in last seconds of its upward journey. If the same shuttle cork is hitted upward with a velocity of $200\, m / s$ then what will be the distance travelled in last second of its upward journey?

Motion in a Straight Line

Solution:

$S = u -\frac{ a }{2}(2 n -1)$
$3=50-\frac{10}{2}(2 n-1)$
$3=50-\left(\frac{20 n }{2}-5\right)$
$\Rightarrow 3=50-10 n+5$
$\Rightarrow 10 n=52$
$\Rightarrow n =5.2$
$S =200-\frac{10}{2}(2 \times 5.2-1)$
$=200-47=153$