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Q. A short bar magnet with a magnetic moment of $ 0.5\text{ }J/T $ is placed in a uniform external magnetic field of 0.16 T in such a way that the magnetic moment vector is anti-parallel to the direction of the magnetic field. The potential energy of the bar magnet is:

KEAMKEAM 2000

Solution:

The potential energy is given by $ U=-M.B $ Given $ M=0.5\text{ }J/T,\text{ }B=0.16\text{ }T. $ $ \therefore $ $ U=-0.5\times 0.16 $ $ U=0.08\text{ }J $