1. Tardigrade
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  3. Physics
  4. A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 0.05 Nm. The magnitude of the magnetic moment of the magnet is

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Q. A short bar magnet placed with its axis at $30^\circ$ with a uniform external magnetic field of $0.25\,T$ experiences a torque of magnitude equal to $0.05\,Nm$. The magnitude of the magnetic moment of the magnet is

Solution:

$\tau = MB\, sin \theta$
$M= \frac{\tau}{B\times sin\theta}=\frac{0.05\times2}{0.25}=0.4 JT^{-1}$