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  4. A shell of mass 5M, acted upon by no external force and initially at rest, bursts into three fragments of masses M, 2M and 2M respectively. The first two fragments move in opposite directions with velocities of magnitudes 2v and v respectively. The third fragment will

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Q. A shell of mass $5M$, acted upon by no external force and initially at rest, bursts into three fragments of masses $M, 2M$ and $2M$ respectively. The first two fragments move in opposite directions with velocities of magnitudes $2v$ and $v$ respectively. The third fragment will

WBJEEWBJEE 2013Laws of Motion

Solution:

Let the velocity of third fragment is $v$. Then by the
conservation of linear momentum
$ 5(0)=M \times 2 v -2 M \times v+2 M \times v^{\prime} $
$\Rightarrow v^{\prime}=0$