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  4. A set of 24 tuning forks are so arranged that each gives 6 beats/s with the previous one. If the frequency of the last tuning fork is double that of the first, frequency of the second tuning fork is

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Q. A set of $24$ tuning forks are so arranged that each gives $6$ beats/s with the previous one. If the frequency of the last tuning fork is double that of the first, frequency of the second tuning fork is

WBJEEWBJEE 2007

Solution:

The frequencies of tuning forks are the terms of an $A P$ whose common difference is $6$ .
$\therefore l=a+(n-1) d$
$2 a=a+(24-1) \times 6$
$a=23 \times 6$
$=138$
$\therefore $ Second frequency
$=138+6=144\, H z$