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  4. A set A has 3 elements and another set B has 6 elements. Then

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Q. A set $A$ has $3$ elements and another set $B$ has $6$ elements. Then

Sets

Solution:

We have
$\min n ( A \cup B )=\max \{ n ( A ), n ( B )\}=\max \{3,6\}=6$
Max $n(A \cup B)=n(A)+n(B)=9 $;
$ \therefore 6 \leq n(A \cup B) \leq 9$