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  4. A set A has 3 elements and another set B has 6 elements. Then

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Q. A set A has 3 elements and another set B has 6 elements. Then

Sets

Solution:

We have
min n (A $\cup$ B) = max {n(A), n (B)}
= max {3, 6} = 6
Max n (A $\cup$ B) = n (A) + n (B) = 9
$\therefore \, 6 \le n (A \cup B) \le 9$