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Q. A schematic plot of In $K_{eq}$ versus inverse of temperature for a reaction is shown below
image
The reaction must be

AIIMSAIIMS 2011

Solution:

Variation of $K_{e q}$ with temperature $T$ is given by van't-Hoff equation.
$\log K_{ eq }=-\frac{\Delta H ^{\circ}}{2.303\, RT }+\frac{\Delta S^{\circ}}{ R }$
Slope of the given line is positive indicating that term $A$ is positive thus $\Delta H^{\circ}$ is negative.
Thus. reaction is exothermic.