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Tardigrade
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Chemistry
A saturated solution prepared by dissolving Ag2CO3 in water has [Ag+]=2.56× 10-4M. Hence, its Ksp is
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Q. A saturated solution prepared by dissolving $ A{{g}_{2}}C{{O}_{3}} $ in water has $ [A{{g}^{+}}]=2.56\times {{10}^{-4}}M. $ Hence, its $ {{K}_{sp}} $ is
VMMC Medical
VMMC Medical 2013
A
$ 8.4\times {{10}^{-12}} $
B
$ 1.68\times {{10}^{-13}} $
C
$ 6.6\times {{10}^{-8}} $
D
$ 1.6\times {{10}^{-2}} $
Solution:
$ A{{g}_{2}}C{{O}_{3}}\rightleftharpoons 2A{{g}^{+}}+CO_{3}^{2-} $ $ [A{{g}^{+}}]=2.56\times {{.0}^{-4}}M $ $ [CO_{3}^{2-}]=\frac{[A{{g}^{+}}]}{2}=1.28\times {{10}^{-4}}M $ $ {{K}_{sp}}={{[A{{g}^{+}}]}^{2}}[CO_{3}^{2-}] $ $ ={{(2.56\,\times \,{{10}^{-4}})}^{2}}(128\times {{10}^{-4}}) $ $ =8.4\times {{10}^{-12}} $