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Q. A satellite moves in elliptical orbit about a planet. Its maximum and minimum velocities of satellites are $ 3\times 10^4 \, m/s $ and $ 1 \times 10^3 \, m/s $ respectively. What is the minimum distance of satellite from planet is maximum distance if $ 4 \times 10^4\, km $

UPSEEUPSEE 2010Gravitation

Solution:

If no external torque acts on a system, then angular momentum of the system does not change.
ie, If $\tau=0$
$\Rightarrow \frac{d L}{d t} =0$
$\therefore L=$ constant
Hence,
$m v_{\max } r_{\min } =m v_{\min } r_{\max }$
$\Rightarrow r_{\min } =\frac{v_{\min } \times r_{\max }}{v_{\max }}$
$=\frac{1 \times 10^{3} \times 4 \times 10^{4}}{3 \times 10^{4}}$
$=\frac{4}{3} \times 10^{3}\, km$