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Q. A sample of nitric acid is $69 \%$ by mass and it has a concentration of $15.44$ moles per litre. Its density is

Some Basic Concepts of Chemistry

Solution:

Volume of $100\, g$ sample $=\frac{\text { Mass }}{\text { Density }(d)}$
$=100 / d$
Molarity $=\frac{\text { Mass of solute }}{\text { Molar mass of solute }} \\ \times \frac{1000}{\text { Volume of solution }(\text { in mL) }}$
Molarity $=\frac{69}{63} \times \frac{1}{100 / d} \times 1000$
$15.44 =\frac{69}{63} \times \frac{1}{100 / d} \times 1000$
$d =\frac{63 \times 15.44}{69 \times 10}=1.409 \,g / cc \approx 1.41\, g / cc$