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Q. A sample of calcium carbonate $\left(CaCO_3\right)$ has the following percentage composition: $Ca = 40\%; C = 12\%; O = 48\%$
If the law of constant proportions is true, then the weight of calcium in $4 g$ of a sample of calcium carbonate obtained from another source will be

Some Basic Concepts of Chemistry

Solution:

In $100\, g\, CaCO _{3},\, 40\, g\, Ca$ is present.
In $4\, g\, CaCO _{3}$, Let $x\, g\, Ca$ be present
$\frac{ x }{4}=\frac{40}{100}$
$\Rightarrow x =1.6\, g$