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Q.
A sample of ammonium phosphate $\left( NH _{4}\right)_{3} PO _{4}$ contains $3.18$ moles of $H$ -atom. The number of moles of $O-$ atom in the sample is
ManipalManipal 2013
Solution:
Number of moles of $O$ atoms $=\frac{1}{3}$ moles of $H$ atoms
$=\frac{1}{3} \times 3.18=1.06 \,mol$