Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A sample of ammonium phosphate $\left( NH _{4}\right)_{3} PO _{4}$ contains $3.18$ moles of $H$ -atom. The number of moles of $O-$ atom in the sample is

ManipalManipal 2013

Solution:

Number of moles of $O$ atoms $=\frac{1}{3}$ moles of $H$ atoms
$=\frac{1}{3} \times 3.18=1.06 \,mol$