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  4. A sample of 0.125 g of an organic compound when analysed by Duma's method yields 22.78 mL of nitrogen gas collected over KOH solution at 280 K and 759 mm Hg. The percentage of nitrogen in the given organic compound is (Nearest integer). (a) The vapour pressure of water at 280 K is 14.2 mm Hg (b) R =0.082 L atm K -1 mol -1

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Q. A sample of $0.125 \,g$ of an organic compound when analysed by Duma's method yields $22.78 \,mL$ of nitrogen gas collected over $KOH$ solution at $280 \,K$ and $759\, mm \,Hg$. The percentage of nitrogen in the given organic compound is ____ (Nearest integer).
(a) The vapour pressure of water at $280\, K$ is $14.2\, mm\, Hg$
(b) $R =0.082 \,L\, atm \,K ^{-1} \,mol ^{-1}$

JEE MainJEE Main 2022Organic Chemistry – Some Basic Principles and Techniques

Solution:

$ V =22.78\, ml , T =280\, K $
$ P _{\text {total }}=759\, mm\, Hg$
$ P _{ N _2}=759-14.2=744.8 \, mm\, Hg $
$ n _{ N _2}=\frac{744.8 \times 22.78}{760 \times 1000 \times 0.082 \times 280}=0.00097$
$ W _{\text {Nitrogen }}=0.02716$
$\% N =\frac{0.02716}{0.125} \times 1000=21.728$