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  4. A salt X is dissolved in water having pH =7. The resulting solution has a pH more than 7. The salt is made by neutralisation of

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Q. A salt $X$ is dissolved in water having $pH =7$. The resulting solution has a pH more than $7$. The salt is made by neutralisation of

Equilibrium

Solution:

$pH \,> 7$ implies the solution is basic. Since salt on hydrolysis in water gives basic solution. Therefore, it is a salt of weak acid strong base and undergoes anionic hydrolysis in aqueous solution
$A^{-} +HOH \rightleftharpoons HA+OH^{-}$