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Q. A rod has non-uniformly distributed mass $M$ over its length $L$ . Its linear mass density variation with distance $x$ from the left end is shown in the figure. From this information, we can conclude that the centre of mass of the rod,
Question

NTA AbhyasNTA Abhyas 2022

Solution:

The area under $\lambda $ versus $x$ curve gives mass.
The area of $I>$ area of $II$ . It means more mass is on the left side. So, the centre of mass would be in the left half.
Solution