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Q. A rocket is receding from earth with a velocity $ 0.2c $ . It emits a signal of frequency $ 4\times {{10}^{7}}Hz $ . The frequency as observed on earth will be:

Rajasthan PMTRajasthan PMT 1996

Solution:

Apparent frequency $ v=v\left( 1-\frac{\upsilon }{c} \right) $ $ =4\times {{10}^{7}}\left( 1-\frac{0.2c}{c} \right)=3.2\times {{10}^{7}}Hz $